-16x^2+64x+4032=0

Solution for -16x^2+64x+4032=0 equation:

-16x^2+64x+4032=0

a = -16; b = 64; c = +4032;
Δ = b2-4ac
Δ = 642-4·(-16)·4032
Δ = 262144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{262144}=512$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-512}{2*-16}=\frac{-576}{-32}
=+18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+512}{2*-16}=\frac{448}{-32}
=-14
$